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The angular momentum of an electron in a...

The angular momentum of an electron in a Bohr's orbit of hydrogen atom is `3.1655xx10^(-34)kg*m^(2)*s^(-1)`. Calculate the wavelength of the spectral line emitted when an electron falls from this level to the next lower level.

Text Solution

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Angular momentum of an electron in 'n-th' Bohr orbit of H-atom, `mvr=(nh)/(2pi) or, 3.1655xx10^(-34)=(nxx6.626xx10^(-34))/(2xx3.14)`
or, `n=(3.1655xx10^(-34)xx2xx3.14)/(6.626xx10^(-34))=3`
`overline(v)=(1)/(lamda)=109677((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))cm^(-1)`
`=109677((1)/(2^(2))-(1)/(3^(2)))" "[becausen_(1)=2,n_(2)=3]`
`lamda=6.564xx10^(-5)cm`
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