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Calculate the kinetic energy of an alpha...

Calculate the kinetic energy of an `alpha`-particle which has a de broglie wavelength 8 pm.

Text Solution

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`lamda=(h)/(mv) or, (h)/(mlamda)=(6.626xx10^(-34))/((6.64xx10^(-27))xx(8xx10^(-12)))`
`=1.247xx10^(4)m*s^(-1)" "[because 1"pm"=10^(-12)m]`
`therefore`Kinetic energy of the `alpha`-particle`=(1)/(2)mv^(2)`
`=(1)/(2)xx(6.64xx10^(-27))xx(1.247xx10^(4))^(2)J=5.16xx10^(-19)J`.
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