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The kinetic energy of a subatomic partic...

The kinetic energy of a subatomic particle is `3.60xx10^(-24)`J. calculate the frequency of the corresponding particle wave.

Text Solution

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Kinetic energy `=(1)/(2)mv^(2)=3.60xx10^(-24)J`
`therefore mv^(2)=2xx3.60xx10^(-24)J=7.2xx10^(-24)J`
For any given wave, `lamda=(v)/(nu)`
`therefore (h)/(mv)=(v)/(nu) or, v=(mv^(2))/(h)=(7.2xx10^(-24))/(6.626xx10^(-34))=1.086xx10^(10)s^(-1)`
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