Derive a relation between kinetic energy and de Broglie wavelength associated with a moving electron.

Explanation

We know, kinetic energy (E) of the particle moving with velocity v, is given by, `E=(1)/(2) or, 2E=mv^(2)`
or, `2mE=m^(2)v^(2)" "therefore mv=sqrt(2mE)`
Now, de broglie wavelength associated with an electron in motion is given by, `lamda=(h)/(mv)=(h)/(sqrt(2mE))`
`therefore` The required relation is `lamda=(h)/(sqrt(mE))`.