Write down the electronic configurations of Ni and `Ni^(2+)` (atomic number of Ni=28). How many odd electrons do each of them contain?

Explanation

`""^(28)Ni:1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(8)4s^(2)`

`therefore`Number of odd electrons=2,
Electronic configuration of `Ni^(2+):1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(8)`

`therefore`Number of odd electrons present in `Ni^(2+) and ` ion=2.