What is the maximum number of electrons present in subshell, (s), for which n+l=3?

Explanation

According to the given conditions,
(a) if n=3, then l=0 (since n+l=3). These two values of quantum numbers indicate 3s-subshell. 3s-subshell can hold maximum of 2 electrons.
(b) Again, if n=2, thenn l=1 (since n+l=3). These two values of quantum numbers denote 2p. subshell. 2p-subshell may contain maximum of 6 electrons.
So, a total of (2+6)=8 electrons will be present in subshell for which n+l=3.