(i) In neon (Ne) atom, how many electrons are there which spin in anti-clockwise direction?
(2) For how many electrons of Cl-atom, n+l=3?

Explanation

(1) Electron configuration of Ne (atomic no.=10)

Each of the 5 orbitals (1s,2s,`2p_(x),2p_(y),2p_(z)`) present in Ne atom contains one electron pair each, as displayed by its electronic configuration. But one of the two electrons in each orbital spins in the clockwise direction whicle the other spins in the anti-clockwise direaction. out of these 10 elctrons, 5 electrons spin in the anti-clockwise direction.
(2) Electronic configuration of `Cl:1s^(2)2s^(2)2p^(6)3s^(2)3p^(5)`
In case of 2 electrons in 1s-subshell n+l=1+0=1
In case of 6 electrons in 2s-subshell, n+l=2+0=2
In case of 6 electrons in 2p-subshell, n+l=2+1=3
In case of 2 electrons in 3s-subshell, n+l=3+0=3
In case of 5 electrons in 3p-subshell, n+l=3+1=4
It is observed that in case of 6 electrons in 2p-subshell annd 2 electrons in 3s-sub-shell, the value of n+l will be equal to 3.