If the energy of first Bohr's orbit is -13.58 eV of a hydrogen atom, calculate the energy of third Bohr's orbit of that atom.

Explanation

According to Bohr's theory,
`E_(n)=-13.58xx(Z^(2))/(n^(2))eV=-13.58xx(1^(2))/(3^(2))eV=-1.5089eV`