The energy of an electron if first Bohr orbit of H-atom is -13.6eV. The possible energy value of electron in the excite statre of `Li^(2+)` is-

Options

A. `-122.4eV`
B. `30.6eV`
C. `-30.6eV`
D. `13.6eV`

Answer

C

Explanation

Energy of an electron in the n-th shell, `E_(n)=(E_(1))/(n^(2))xxZ^(2)`
For `Li^(2+),Z=3 and` is excited state n=2. so, the possible value of energy`=(-13.6)/(4)xx9=-30.6eV`.