The nucleus ""(29)^(64)Cu accepts an orb...

The nucleus `""_(29)^(64)Cu` accepts an orbital electron to yield-

`""_(28)^(65)Ni`

`""_(30)^(64)Zn`

`""_(28)^(64)Ni`

`""_(30)^(65)Zn`

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The correct Answer is:

`""_(29)^(64)Cu+_(-1)^(0)e to ""_(28)^(64)Ni`

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