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Energy of electron is given by E=-2.178x...

Energy of electron is given by `E=-2.178xx10^(-18)((Z^(2))/(n^(2)))`J.
Wavelength of light required to excited an electron in an hydrogen atom from level n=1 to n=2 will be `(h=6.62xx10^(-34)J*s and c=3.0xx10^(8)m*s^(-1))`-

A

`8.500xx10^(-7)m`

B

`1.214xx10^(-7)m`

C

`2.816xx10^(-7)m`

D

`6.500xx10^(-7)m`

Text Solution

Verified by Experts

The correct Answer is:
B

`E=-2.178xx10^(-8)Z^(2)((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))`
`=-2.178xx10^(-8)[(1)/((2)^(2))-(1)/((1)^(2))]" "[For " "H,Z=1]`
`=1.6335xx10^(-18)J`
Again, `lamda=(hc)/(E)=(6.62xx10^(-34)xx3xx10^(8))/(1.6335xx10^(-18))=1.214xx10^(-7)m`
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