The energies `E_(1) and E_(2)` of two radiations are 25eV and 50eV respectively. The relation between their wavelengths i.e., `lamda_(1) and lamda_(2)` will be-

Options

A. `lamda_(1)=lamda_(2)`
B. `lamda_(1)=2lamda_(2)`
C. `lamda_(1)=4lamda_(2)`
D. `lamda_(1)=(1)/(2)lamda_(2)`

Answer

B

Explanation

`E_(1)=(hc)/(lamda_(1)) and E_(2)=(hc)/(lamda_(2))" "therefore (E_(1))/(E_(2))=(hc)/(lamda_(1))xx(lamda_(2))/(hc)=(lamda_(2))/(lamda_(1))`
or, `(25)/(50)=(lamda_(2))/(lamda_(1)) or, lamda_(1)=2lamda_(2)`