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Calculate the energy in joule correspond...

Calculate the energy in joule corresponding to light of wavelength 45 nm. (plancks constant, `h=6.63xx10^(-34)J*s`, speed of light `c=3xx10^(8)m*s^(-`))-

A

`6.67xx10^(15)`

B

`6.67xx10^(11)`

C

`4.42xx10^(-15)`

D

`4.42xx10^(-18)`

Text Solution

Verified by Experts

The correct Answer is:
D
`E=(hc)/(lamda)=(6.626xx10^(-34)xx3xx10^(8))/(45xx10^(-9))=4.42xx10^(-18)J`
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