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Threshold frequency of a metal is 5xx10^...

Threshold frequency of a metal is `5xx10^(13)s^(-1)` upon which `1xx10^(14)s^(-1)` frequency light is focused. Then the maximum kinetic energy of emitted electron is-

A

`3.3xx10^(-21)J`

B

`3.3xx10^(-20)J`

C

`6.6xx10^(-21)J`

D

`6.6xx10^(-20)J`

Text Solution

Verified by Experts

The correct Answer is:
B
Following the conservation of energy principle,
Kinetic energy `((1)/(2)m_(e)v^(2))=h(v-v_(0))`
`=(6.626xx10^(-34)J*s)(1x10^(14)-5xx10^(13))s^(-1)`
`=(6.626xx10^(-34)J*s)(5xx10^(13)s^(-1))`
`=3.313xx10^(-20)J`
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