Calculate the velocity of an electron placed in the second orbit of `Li^(2+)` ion-

Options

A. 0.521`m*s^(-1)`
B. `3.27xx10^(6)cm*s^(-1)`
C. `4.23xx10^(3)m*s^(-1)`
D. `3.27xx10^(6)m*s^(-1)`

Answer

D

Explanation

The velocity of an electron in nth shell of the hydrogen like atom `=(2.18xx10^(6)m*s^(-1)xxZ)/(n)`
On putting Z=3 and n=2,
`v=(2.18xx10^(6)xx3)/(2)=3.27xx10^(6)m*s^(-1)`.