Calculate the velocity `(cm*s^(-1))` and frequency of revolution of electron present in the 3rd orbit of H-atom.

Explanation

Velocity of revolving electron present in the 3rd orbit of H-atom
`=(2pize^(2))/(nh)=(2xxpixx1xx(4.8xx10^(-10))^(2))/(3xx6.626xx10^(-27))`
`=7.27xx10^(7)cm*s^(-1)`
Frequency of revolution of electron
`=(v)/(2pir)=(v)/(2pi((n^(2)h^(2))/(4pi^(2)mze^(2))))=(2pimvze^(2))/(n^(2)h^(2))`
`=(2xx3.14xx(9.11xx10^(-28))xx(7.27xx10^(7))xx1xx(4.8xx10^(-10))^(2))/((3)^(2)xx(6.626xx10^(-27))^(2))`
`=2.42xx10^(14)`.
Frequency`=2.42xx10^(14)Hz`.