Calculate the frequency nad wave length of the energy emitted when the electron jumps from 4th orbit to 1st orbit of a H-atom.

Explanation

`overline(v)=(1)/(lamda)=1.09678xx10^(7)xx((1)/(1^(2))-(1)/(4^(2)))=10.28xx10^(6)m^(-1)`
`therefore`Wavelength, `lamda=(1)/(10.28xx10^(6))=9.73xx10^(15)m`
Frequency, `v=(c)/(lamda)=(3xx10^(8)m*s^(-1))/(9.73xx10^(-8)m)=3.1xx10^(15)s^(-1)`.