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The ionisationn potential of sodium is 4...

The ionisationn potential of sodium is `4.946xx10^(2)kJ*mol^(-1)`. Calculate the wavelength of the radiation required to ioinise a sodium atom.

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Ionisation potential of sodium
`=(((4.946xx10^(2))xx10^(3))/(6.022xx10^(23))J*"atom"^(_1))`
`=8.21xx10^(-19)J*"atom"^(-1)`
Now, `lamda=(hc)/(E)=((6.626xx10^(-34))xx(3xx10^(8)))/(8.21xx10^(-19))`m
`=242xx10^(-9)m=242nm`.
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