The ionisation potential of H-atom is 13.6 eV. Calculate the ionisation potential of `He^(+)` and `Li^(2+)` ions.

Explanation

`IE_((He^(2+)))=IE_((H))xx(z^(2))/(n^(2))=13.6xx(2^(2))/(1^(2))=54.4eV`
`IE_((Li^(2+)))=IE_((H))xx(z^(2))/(n^(2))=13.6xx(3^(2))/(1^(2))=122.4eV`.