Calculate the velocity of an electron in the first Bohr obit. Also calculate the de Broglie wavelength (in 'm') of the electron. Find the orbital angular momentum (in `(h)/(2pi)` units) of 3p orbital of hydrogen atom.

Explanation

Velocity of electron in the n-th orbit of H-atom is given by
`v_(n)=(2.188xx10^(6))/(n)m*s^(-1)`
`therefore`Velocity of electron in the first orbit of H-atom,
`v_(1)=2.188xx10^(6)m*s^(-1)`
The de Broglie wavelength, `lamda=(h)/(mv)`
`=(6.626xx10^(-34))/(9.11xx10^(-31)xx2.188xx10^(6))=3.32xx10^(-10)m`
Orbital angular angular momentum, `L=sqrt(l(l+1))(h)/(2pi)`
`=sqrt(l(l+1))(h)/(2pi)`
`=sqrt(2)(h)/(2pi)" "[because l=1 " for "3p]`.