It is correct to say that bond order always increases with loss of electron? Explain your answe.

Explanation

the statement is not always correct. When an electron is expelled from a bonding MO, the bond order decreases, but when an electron is expelled from antibonding MO, the bond order increases. For example, loss of an electron from `H_(2)(sigma_(1s))^(2)(sigma_(1s)^(**))^(0)` to from `H_(2)^(+)(sigma_(1s))^(1)(sigma_(1s)^(**))^(0)` result in decrease of bond order. however, loss of an electron from `H_(2)^(-)(sigma_(1s))^(2)(sigma_(1s)^(**))^(1)` to form `H_(2)(sigma_(1s))^(2)(sigma_(1s)^(**))^(0)` results in increase of bond order. bond order of `H_(2)^(+)=(1)/(2)(1-0)=(1)/(2),H_(2)=(1)/(2)(2-0)=1,H_(2)^(-)=(1)/(2)(2-1)=(1)/(2)`.