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At constant temperature and pressure the rate of diffusion of `H_(2)` gas is `sqrt(15)` times that of `C_(n)H_(4n-2)` gas. Find the value of n.

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Verified by Experts

`(r_(H_(2)))/(c_(C_(n)H_(4n-2))=sqrt((16n-2)/(2))=sqrt(8n-1)=sqrt(15)`
or, `8n-1=15` or, n=2.
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CHHAYA PUBLICATION-STATES OF MATTER : GASES AND LIQUIDS-WARM UP EXERCISE
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  3. At constant temperature and pressure the rate of diffusion of H(2) gas...

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  4. Under the same conditions, a gas diffuses sqrt(2) times as fast as SO(...

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  5. Besides the lower layer, CO(2) is also found in the upper layer of the...

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  17. According to the kinetic theory of gases, the average kinetic energies...

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