A closed vessel holds a gas mixture consisting of `C_(2)H_(6),C_(2)H_(4) and CH_(4)`, each with an amount of 2.5 mol. But due to a pinhole is the vessel, the gas mixture undergoes effusion. What will be the order of partial pressures of the gases in the vessel after sometime?

Explanation

Molar masses of `C_(2)H_(6),C_(2)H_(4) and CH_(4)` follows the order: `m_(CH_(4)) lt m_(C_(2)H_(4)) lt M_(C_(2)H_(6))`. Thus, at a certain temperature and pressure their rates of effusion will be in the order: `r_(C_(2)H_(6)) lt r_(C_(2)H_(4)) lt r_(CH_(4))`, and consequently the number of moles left in the vessel after some time will be in the order: `n_(CH_(4)) lt n_(C_(2)H_(4)) lt n_(C_(2)H_(6))`. Therefore, the order of partial pressure after some time will be: `p_(CH_(4)) lt p_(C_(2)H_(4)) lt p_(C_(2)H_(6))`.