At a given temperature, the root mean square velocities of the molecules of gases A, and B are x and ycm`*s^(-1)`, respectively. If x is greater than y, then which gas has larger molar mass?

Explanation

For gas A: `c_(rms)=sqrt((3RT)/(M_(A)))=x" cm"*s^(-1)`
For gas B: `c_(rms)=sqrt((3RT)/(M_(B)))=y" cm"*s^(-1)`
`therefore (x)/(y)=sqrt((M_(B))/(M_(A)))`, sinec `x gt y, M_(B)` will be greater than `M_(A)`.