At a definite temperature, the total pressure of a gas-mixture consisting of three gases A, B and C is P. If the number of moles of A, B and C are 2, 4 and 6, respectively, then arrange these gases in increasing order of their partial pressures.

Explanation

The mole fractions of A, B and C in the gas mixture,
`x_(A)=(2)/(12)=(1)/(6),x_(B)=(4)/(12)=(1)/(3) and x_(C)=(6)/(12)=(1)/(2)`
Therefore, the partial pressure of gas, A `p_(A)=(P)/(6),p_(B)=(P)/(3)`
`p_(C)=(P)/(2)`. Hence `p_(A) lt p_(B) lt p_(C)`.