Under idential conditoins of temperature and pressure, it takes time `t_(1)` for the effusion of VmL of `N_(2)` gas through a porous wall and the time `t_(2)` for the effusion of the same volume of `CO_(2)` gas through the same porous wall. Which one is greater `t_(1) or t_(2)`?

Explanation

At constant temperature and pressure, the rates of effusion of different gases are inversely proportional to the square roots of their molar masses. As the molar mass of `N_(2)` is small than that of `CO_(2)`, at the given conditions the time required for the effusion of V mL of `N_(2)` gas will be less than that required for V mL `CO_(2)` of gas. hence, `t_(1) lt t_(2)`.