Calculate the total number of electrons present in 1.4 g of dinitrogen gas.

Explanation

1.4 g of `N_(2)=(1.4)/(28)=0.05` mol of `N_(2)`
1 molecules of `N_(2)` contains 14 electrons.
Hence, 0.05 mol of `N_(2)`, i.e., `0.05xx6.022xx10^(23)`
molecules of `N_(2)` contain `14xx0.5xx6.023xx10^(23)`
`=4.2154xx10^(23)` electrons.