Calculate the volume occupied by 8.8 g of `CO_(2)` at `31.1^(@)C` & 1 bar pressure. R=0.083 bar `*L*K^(-1)mol^(-1)`.

Explanation

8.8g `CO_(2)=(8.8)/(44)=0.2` mol `CO_(2)` [Molar mass of `CO_(2)=44g*mol^(-1)`]
Applying ideal gas equation (PV=nRT) to calculate
volume, we have `V=(nRT)/(P)=(0.2xx0.083xx(273+31.1))/(1)=5.048L`
`therefore`Volume of 8.8g `CO_(2)` at `31.1^(@)C` and 1 bar pressure=5.048 L.