0.0286g of a gas at 25^(@)C and 76 cm pr...

0.0286g of a gas at `25^(@)C` and 76 cm presure occupies a volume of `50cm^(3)`. What is molarr mass of the gas?

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`M=(gRT)/(PV)=(0.0286xx0.0821xx298)/(1xx50xx10^(-3))=14g*mol^(-1)`

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