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The temperature of an ideal gas is 340 K...

The temperature of an ideal gas is 340 K. the gas is heated to a temperature at constant pressure. As a result, its volume increases by 18%. What is the final temperature of the gas?

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`(V_(2))/(V_(1))=(T_(2))/(T_(1)) or, ((1.18)V_(1))/(V_(1))=(T_(2))/(3340),` hence `T_(2)=401.2K`.
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