At constant temperature and pressure, the rates of diffusion of two gases A and B are in the ratio of 1:2 . In a mixture of A and B gases if the mass ratio of A and B be 2:1, the find the mole fraction ratio of A and B in the mixture?

Explanation

`r_(A)/r_(B)=sqrt((M_(B))/(M_(A))) or, (1)/(2)=sqrt((M_(B))/(M_(A))) or, M_(A)=4M_(B)`
`(W_(A))/(W_(B))=2 or, (n_(A)xxM_(A))/(n_(B)xxM_(B))=2 or, (n_(A))/(n_(B))=(1)/(2)," "therefore (x_(A))/(x_(B))=(n_(A))/(n_(B))=(1)/(2)`