A certain gas of mass 6.431 g occupies a volume of 5 L at a definite temperature and 750 mm pressure. At the same temperature, what will be the rms velocity of the molecules of that gas?

Explanation

`PV=nRT=(W)/(M)RT or, (RT)/(M)=(PV)/(W)=(750)/(760)xx5xx(1)/(6.431)g^(-1)`
`=0.7672L*atm*g^(-1)`
`=0.7672xx10^(3)xx1.013xx10^(6)cm^(2)*s^(-2)`
`[because1atm=1.013xx10^(6)g*cm^(-1)*s^(-2)]`
`therefore c_(rms)=sqrt((3RT)/(M))=sqrt(3xx0.7672xx1.013xx10^(9))cm//s`