In a container of volume 1L, there are `10^(23)` gas molecules, each of which has a mass of `10^(-22)` g. at a certain temperature, if the rms velocity of these molecules is `10^(5)cm*s^(-1)`, then what would be the pressure at the temperature inside the container?

Explanation

`PV=(1)/(3)mnc_(rms)^(2)`
or, `Pxx1000=(1)/(3)xx10^(-22)xx10^(23)xx(10^(5))^(2)`
`therefore P=3.33xx10^(10)g*cm^(-1)*s^(-2)`
`=3.33xx10^(10)`dyne =32.87 atm