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Compressibility factor of a real gas at ...

Compressibility factor of a real gas at `0^(@)C` and 100 atm pressure is 0.927. at this temperature and pressure, how much of this real gas is required to fill a vessel of 100 L [molar mass=`40g*mol^(-1)`] ?

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`Z=(PV)/(nRT) or, 0.927=(100xx100)/(nxx0.0821xx273)`
`therefore n=481.298` mol
`therefore `Amount of gas required`=481.298xx40g=19.2519kg`.
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