A metal complex `Cr(NH_(3))_(4)Cl_(2)` having molar conductivity corresponding to `1:1` electrolyte have been isolated in two Forms (X) and (Y), (X) reacts with `AgNO_(3)` giving white precipitate which turns yellow on reaction with sodium arsenite whereas (Y) gives a yellow precipitate soluble in concentrate `NH_(4)OH`
The correct formula and the IUPAC name of the complex (X) is :

Options

A. `[Cr(NH_(3))_(4)Cl_(2)]Br` and tetraaminedichloridochromate(II) bromide.
B. `[Cr(NH_(3))_(4)ClBr]Cl` and tetraamminebromidochloridochromate(II) chloride.
C. `[Cr(NH_(3))_(4)ClBr]Cl` and tetramminebromidochloridochromium(III) chloride.
D. `[Cr(NH_(3))_(4)ClBr]Cl` and tetraamminebromidochloridochromium(III) chloride.

Answer

D

Explanation

`underset(d^(3))(X) to underset(d^(2)sp^(3))[Cr(NH_(3))_(4)ClBr]Cl,(Y) to underset(d^(2)sp^(3),mu=3.8 B.M.)[Cr(NH_(3))_(4)Cl_(2)]Br`
`"EAN" to 24-3+12=33`
Both X and Y can show G.I.