Find the number of compound which has four orbitals participating in hybridisation in central atom.
`(a) K_(2)CrO_(4)" "(b) K_(2)Cr_(2)O_(7)`
`(c ) KMnO_(4)" "(d) K_(2)MnO_(4)`
`(e ) [Ni(CN)_(4)]^(2-)" "(f) [NiCl_(4)]^(2-)`
`(g) [PtCl_(4)]^(2-)" "(h) Na_(4)P_(2)O_(7)`
`(i) H_(2)S_(2)O_(8)`

Answer

9

Explanation

`underset(d^(3)s)ubrace(a,b,c,d,)underset(dsp^(2))underset(darr)e,underset(sp^(3))underset(darr)f,underset(dsp^(2))underset(darr)g,underset(sp^(3))underset(darr)h,underset(sp^(3))underset(darr)i` ,
All have 4 orbitals in hyb.