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(1)/(4)[Li(CH(3))(4)]+[Mo(CO)(6)] to [X]...

`(1)/(4)[Li_(CH_(3))_(4)]+[Mo(CO)_(6)] to [X]`
Here X is Lithium acetylpentacarbonyllmolybdate(1-), then find the total number of Mo-C linkages in the complex X

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The correct Answer is:
6
`X=Li[Mo(CH_(3)CO)(CO)_(5)]`
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