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How many of the following complexes are ...

How many of the following complexes are expected to have `d^(2)sp^(3)` hybridisation ?
`[Mn(CN)_(6)]^(3-)," "[MnCl_(6)]^(3-),`
`[Fe(CN)_(6)]^(3-),[FeF_(6)]^(3-)," "[CoF_(6)]^(3-),`
`[Co(C_(2)O_(4))_(3)]^(3-)," "[MnBr_(4)]^(2-)`

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To determine how many of the given complexes exhibit `d^(2)sp^(3)` hybridization, we need to analyze each complex based on the oxidation state of the central metal ion and the nature of the ligands involved. ### Step-by-Step Solution: 1. **Identify the oxidation state of the central metal ion**: - For each complex, we need to find out the oxidation state of the metal ion. 2. **Determine the electron configuration**: - Based on the oxidation state, we will determine the electron configuration of the metal ion. 3. **Analyze the ligands**: - Identify whether the ligands are strong field or weak field ligands. Strong field ligands cause pairing of electrons, while weak field ligands do not. 4. **Determine the hybridization**: - Based on the number of paired and unpaired electrons, we can determine if the hybridization is `d^(2)sp^(3)`. Now, let's analyze each complex: 1. **[Mn(CN)₆]³⁻**: - Oxidation state of Mn = +3 (since CN is a -1 ligand, 6 * -1 = -6, thus Mn must be +3). - Electron configuration of Mn (Z=25) in +3 state: [Ar] 3d⁴. - CN is a strong field ligand, leading to pairing of electrons: 3d². - Hybridization: `d²sp³`. 2. **[MnCl₆]³⁻**: - Oxidation state of Mn = +3. - Electron configuration of Mn in +3 state: [Ar] 3d⁴. - Cl is a weak field ligand, so no pairing occurs: 3d⁴. - Hybridization: `sp³d²` (not `d²sp³`). 3. **[Fe(CN)₆]³⁻**: - Oxidation state of Fe = +3. - Electron configuration of Fe in +3 state: [Ar] 3d⁵. - CN is a strong field ligand, leading to pairing of electrons: 3d⁵. - Hybridization: `d²sp³`. 4. **[FeF₆]³⁻**: - Oxidation state of Fe = +3. - Electron configuration of Fe in +3 state: [Ar] 3d⁵. - F is a weak field ligand, so no pairing occurs: 3d⁵. - Hybridization: `sp³d²` (not `d²sp³`). 5. **[CoF₆]³⁻**: - Oxidation state of Co = +3. - Electron configuration of Co in +3 state: [Ar] 3d⁶. - F is a weak field ligand, so no pairing occurs: 3d⁶. - Hybridization: `sp³d²` (not `d²sp³`). 6. **[Co(C₂O₄)₃]³⁻**: - Oxidation state of Co = +3. - Electron configuration of Co in +3 state: [Ar] 3d⁶. - Oxalate (C₂O₄²⁻) is a strong field ligand, leading to pairing: 3d⁶. - Hybridization: `d²sp³`. 7. **[MnBr₄]²⁻**: - Oxidation state of Mn = +2. - Electron configuration of Mn in +2 state: [Ar] 3d⁵. - Br is a weak field ligand, so no pairing occurs: 3d⁵. - Hybridization: `sp³d²` (not `d²sp³`). ### Summary of Findings: - Complexes with `d²sp³` hybridization: - [Mn(CN)₆]³⁻ - [Fe(CN)₆]³⁻ - [Co(C₂O₄)₃]³⁻ Thus, **3 complexes** exhibit `d²sp³` hybridization.

To determine how many of the given complexes exhibit `d^(2)sp^(3)` hybridization, we need to analyze each complex based on the oxidation state of the central metal ion and the nature of the ligands involved. ### Step-by-Step Solution: 1. **Identify the oxidation state of the central metal ion**: - For each complex, we need to find out the oxidation state of the metal ion. 2. **Determine the electron configuration**: ...
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