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The correct order of S(N)2//E2 ratio for...

The correct order of `S_(N)2//E2` ratio for the % yield of product of the following halide is,
P.`CH_(3)-CH_(2)-underset(I) underset(|) overset (Ph) overset(|) (C)-CH_(3)`
Q. `CH_(3)-underset (Ph) underset(|) (CH)-underset(I) underset(|) (CH)-CH_(3)`
R. `CH_(3)-CH_(2)-I`
S. `CH_(3)-CH-underset(I) underset(|) (CH)-CH_(3)`

A

`RgtSgtQgtP`

B

`RgtQgtSgtP`

C

`PgtRgtSgtQ`

D

`QgtPgtRgtS`

Text Solution

Verified by Experts

The correct Answer is:
A
Rate of `S_(N)2` reactionL: `1^(@)gt2^(@)gt3^(@)` as `beta` branching increases steric crowding increases in trasition state so it makes less stable T.S.
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The corrent order of S_(N)2//E_(2) ratio for the % yield of product of the following halide is (P) CH_(3)-CH_(2)-underset(I)underset(|)overset(Ph)overset(|)C -CH_(3) (Q) CH_(3)-underset(Ph)underset(|)CH-underset(I)underset(|)CH -CH_(3) (R) CH_(3) -CH_(2) -I (S) CH_(3)CH_(2)-underset(I)underset(|)CH -CH_(3) .

CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(2)-underset(O)underset(||)(C)-NHCH_(3)

CH_(3)CH_(2)-underset(Ph)underset(|)overset(OH)overset(|)C-CH_(3) cannnot be prepared by:

The IUPAC name of the compound is: CH_(3)-underset(CH_(3))underset(|)(CH)-overset(Ph)overset(|)(CH)-NH_(2)

CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C)-CH_(2)OH

CH_(3)-underset(CH_(3))underset(|)(CH)-CH=CH-CH_(2)-overset(O)overset(||)(C)-OH

CH_(3)-underset(Cl)underset(|)(C )H-underset(I)underset(|)(C )H-CH_(3) CH_(3)-underset(CH_(3))underset(|)(C)H-(CH_(2))_(4)-underset(CH_(3))underset(|)(C )H-underset(Br)underset(|)(C )H-CH_(2)CH_(3)