`S_(N)1` reaction underoges through carbocation intermediate as follows: `R-X(aq.) overset("Slow") hArr R^(+)(aq.)+` `X^(-) (aq.) underset ("fast") overset(H_(2)O)to ROH(aq.)+H^(+)(aq.)` [R=t-Bu, iso-Pr, Me] `(X=Cl, Br, I)` The correct statements are I. The decreasing order of rate of `S_(N)1` reaction is `t-BuXgtiso-PrXgtEtXgtMeX` II. The decreasing order of ionisation energy is `MeXgtEtXgtiso-PrXgt t-BuX` III. The decreasing order of energy of activation is `t-BuX gt iso- PrXgtEtXgtMeX`
A
I & II are correct
B
I & III are correct
C
II and III are correct
D
I, II & III are correct
Text Solution
Verified by Experts
The correct Answer is:
A
Rate of `S_(N)1` reaction is a `tBu X gt iso -Pr Xgt Et gt MeX` So order of activation energy `t-BuX lt iso -PrXC lt EtXlt MeX` order of ionisation energy `t Bu X lt iso-BrX-EtX lt MeX`
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