In an adsorption experiment a graph between log `x/m` versus log `P` was fond to be linear with a slope of `45^@)`. The intercept on the log `x/m` axis was found to `0.70`. Calculate the amount of gas adsorbed per gram of charcoal under a pressure of `1` atm `[log5=0.70]`
A
`5`
B
`2`
C
`3`
D
`0`
Text Solution
Verified by Experts
The correct Answer is:
A
`"log" x/m=logk+1/nlogP` `1/n=tan45^(@)` `:.n=1` `logk=0.70` `:.k=5` Now `x/m=KP^(1//m)` `5(1)^(1/1)=5`
Topper's Solved these Questions
TEST PAPERS
RESONANCE|Exercise PART - III CHEMISTRY SEC - 1|12 Videos
TEST PAPERS
RESONANCE|Exercise PART - III CHEMISTRY SEC - 2|18 Videos
SURFACE CHEMISTRY
RESONANCE|Exercise Section - 5|1 Videos
TEST SERIES
RESONANCE|Exercise CHEMISTRY|50 Videos
Similar Questions
Explore conceptually related problems
In an adsorption experiment, a graph between log (x/m) versus log P was found to be linear with a slope of 45^(@) . The intercept on the log (x/m) axis was found to be 0.3010 . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of 0.5 atm .
In an adsorption experiment, a graph between log (x/m) versus log P was found to be linear with a slope of 45^(@) . The intercept on the log y axis was found to be 0.301 . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of 3.0 atm.
In an Adsorption experiment a graph between log x//m versus log P was found to be linear with a slope of 45^(@) the intercept of the log x//m was found to be 0.3010 . Calculate the amount of gas adsorbed per gm of charcoal under a pressure of 0.6 bar.
A graph between log (x/m) and log p is straight line at an angle of 45^(@) with intercept on y-axis equal to 0.3010. Calculate the amount of the gas adsorbed per gram of the adsobent when the pressure is 0.2 atm.
Graph between log x/m and log P is a straight line at angle of 45^(@) with intercept 0.4771 on y-axis. Calculate the amount of gas adsorbed in gram per gram of adsorbent when pressure is 3 atm.
For adsorption of gas on solid suface. The plots of log x//m versus log P is linear with a slope equal to