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In an adsorption experiment a graph betw...

In an adsorption experiment a graph between log `x/m` versus log `P` was fond to be linear with a slope of `45^@)`. The intercept on the log `x/m` axis was found to `0.70`. Calculate the amount of gas adsorbed per gram of charcoal under a pressure of `1` atm `[log5=0.70]`

A

`5`

B

`2`

C

`3`

D

`0`

Text Solution

Verified by Experts

The correct Answer is:
A

`"log" x/m=logk+1/nlogP`
`1/n=tan45^(@)`
`:.n=1`
`logk=0.70`
`:.k=5`
Now `x/m=KP^(1//m)`
`5(1)^(1/1)=5`
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