The coagulation of `100mL` of a colloidal solution of gold is completely prevented by adding `0.25g` of starch to it before adding `10mL` of `10%NaCl` solution. The gold number of starch is
A
`24`
B
`240`
C
`120`
D
`360`
Text Solution
Verified by Experts
The correct Answer is:
A
`0.024g` or `24mg`
Topper's Solved these Questions
TEST PAPERS
RESONANCE|Exercise PART - III CHEMISTRY SEC - 1|12 Videos
TEST PAPERS
RESONANCE|Exercise PART - III CHEMISTRY SEC - 2|18 Videos
SURFACE CHEMISTRY
RESONANCE|Exercise Section - 5|1 Videos
TEST SERIES
RESONANCE|Exercise CHEMISTRY|50 Videos
Similar Questions
Explore conceptually related problems
The coagulation of 200 ml of a colloidal solution of gold is completely prevented by adding 0.50 gm of starch to it before adding 1 ml of 10% NaCl solution. Calculate the gold number of starch.
The coagulation of 100 mL of a colloidal solution of gold is completely prevented by the addition of 0.030 g of it before adding 1 mL of 10% NaCl solution. Find out the gold number of starch?
The cogulation of 100 mL of colloidal solutionof gold is completely prevented by additionof 0.25 g of substance "X" to it before addition of 1 mL of 10% NaCl solution. The gold number of substance 'X' is :
The coagulation of 100ml of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance "X" to it before addition of 1 ml of 10% NaCI solution. The gold number of "X"is :
The coagulation of 10 ml of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance "X" to it before addition of 1 ml of 10% NaCl solution. The gold number of "X" is
The coagulation of 10cm^(3) of gold sol by 1 ml 10% NaCl solution is completely prevented by addition of 0.025g of starch to it. The gold number of starch is