For an exothermic reaction `ArarrB`, the activation energy is `65kJmol^(-1)` and enthalpy of reaction is `42kJmol^(-1)`. The activation energy for the reaction `BrarrA` will be:
A
`23kJmol^(-1)`
B
`107kJmol^(-1)`
C
`65kJmol^(-1)`
D
`42kJmol^(-1)`
Text Solution
Verified by Experts
The correct Answer is:
B
The given data are shown in the figure. Obviously `E_(a(2))=E_(a(f))+DeltaH=(65+42)kJmol^(-1)`
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