The spin magnetic moment of cobalt in the compound `Hg[Co(SCN)_(4)]` is
A
`sqrt(3)`
B
`sqrt(8)`
C
`sqrt(15)`
D
`sqrt(24)`
Text Solution
Verified by Experts
The correct Answer is:
C
`Hg[Co(SCN)(4)]rarrHg^(2+)+[Co(SCN)_(4)]^(2-)` Oxidation state of cobalt `x+4xx(-1)=-2` `=x4-2=+2` In `+2` oxidation state cobalt have `3` upaired electron `(d^(7)` electronic configurations). So `mu_(S)=sqrt(3(3+2))=sqrt(15)`s B.M.
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