An aqueous glucose solution has boiling point of `374.19K`. Another aqueous glucose solution has a freezing point of `272.22K`. Find the molality ratio of two solution. Boiling point and freezing point of `H_(2)O373.15K` and `273.15K` respectively.

Answer

4

Explanation

`DeltaT_(0)=k_(b).m_(1) DeltaT_(r)=k_(f).m_(2)`
`(T_(b))_(s)-T_(b)^(O)=k_(b)=k_(b).m_(1) T_(f)^(O)-(T_(f))_(s)=k_(f).m_(2)`
`374.19-373.15=0.52xxm_(1)rarr`(A)
`273.15-272.22=1.86xxm_(2)rarr` (B)
`((1))/((2))implies(1.04xx1.86)/(0.93xx0.52)=(1.9344)/(0.4836)=4`