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Pure enantiomer of lactic acid has an op...

Pure enantiomer of lactic acid has an optical rotation of `+1.6^(@)`. A sample of lactic acid has an optical rotatin of `+0.8^(@)`. The enantiomer exces is `Xxx10^(1)%`. Find `X`

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The correct Answer is:
5
Enantiomer excess `=0.8/1.6xx100=50%=5xx10^(1)`
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