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Consider the following standard electrod...

Consider the following standard electrode potentials and calculate `logK_(eq)` at `25^(@)C` for the indicated disproportion reaction. [Take `(2.303RT)/F=0.06V`]
`3MN^(2+)(aq)arrMn(s)+2Mn^(3+)(aq)`
`Mn^(3+)(aq)+e^(-)rarrMn^(2+)(a),E^(@)=1.51V`
`Mn^(2+)(aq)+2e^(-)rarrMn(s),E^(@)=-1.185V`

A

`-21.15`

B

`-48.24`

C

`-89.83`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
`2Mn^(2+)rarr2Mn^(3+)+2e^(-),DeltaG_(1)^(0)`
`Mn^(2+)+2e(-)rarrMn, DeltaG_(2)^(0)`
`3Mn^(2+)(aq)rarrMn(s)+2Mn^(3+)(aq)`
`=2xxFxxE_(3)^(0)=-2xxF[-1.51]-2xxFxx(-1.185)`
`E_(3)^(0)=-2.695V`
`E_(3)^(0)=+(0.06)/2logK_(eq)`
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