How long (in hours) will it take to produce `0.3` mole of `HNO_(2)` by following reaction if an average current of `2` amp passes through the cell? `NO_(3)^(-)+3H_(3)O^(+)+2e^(-)rarrHNO_(2)+4H_(2)O,E^(@)=0.94V`
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The correct Answer is:
8
Total charge `=0.6` mole `=0.6FF=0.6xx96500C` `Q=ixxt=2xxt=0.6xx96500` `t=(0.6xx96500)/2`sec `=8` hour
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