A vessel of 120 mL capacity contains a certain amount of gas at `35^@C` and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at `35^@C`. What would be its pressure?

Explanation

`p_1=1.2 ba r,p_2=? V_1=120mL,V_2=180mL`
According to Boyle's law, `p_1V_1=p_2V_2`
`p_2=(p_1V_1)/V_2=(1.2ba r times 120mL)/(180mL)=0.8 ba r`