What will be the pressure of the gaseous mixture when 0.5 L of `H_2` at 0.8 bar and 2.0 L of dioxygen at 0.7 bar are introduced in a 1 L vessel at `27^@C`?

Explanation

According Dalton's law `p=(p_1V_1+p_2V_2)/V`
`p_1=0.8 ba r , p_2=0.7 ba r ,V_1=0.5L, V_2=2.0 L`
`thereforep=((0.8 ba r times0.5L)+(0.7 ba r times2.0L))/1`
=1.8 bar